Schuss von hohem Gebäude
About points...
We associate a certain number of points with each exercise.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
When you click an exercise into a collection, this number will be taken as points for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit the number of points for the exercise in the collection independently, without any effect on "points by default" as represented by the number here.
That being said... How many "default points" should you associate with an exercise upon creation?
As with difficulty, there is no straight forward and generally accepted way.
But as a guideline, we tend to give as many points by default as there are mathematical steps to do in the exercise.
Again, very vague... But the number should kind of represent the "work" required.
About difficulty...
We associate a certain difficulty with each exercise.
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
When you click an exercise into a collection, this number will be taken as difficulty for the exercise, kind of "by default".
But once the exercise is on the collection, you can edit its difficulty in the collection independently, without any effect on the "difficulty by default" here.
Why we use chess pieces? Well... we like chess, we like playing around with \(\LaTeX\)-fonts, we wanted symbols that need less space than six stars in a table-column... But in your layouts, you are of course free to indicate the difficulty of the exercise the way you want.
That being said... How "difficult" is an exercise? It depends on many factors, like what was being taught etc.
In physics exercises, we try to follow this pattern:
Level 1 - One formula (one you would find in a reference book) is enough to solve the exercise. Example exercise
Level 2 - Two formulas are needed, it's possible to compute an "in-between" solution, i.e. no algebraic equation needed. Example exercise
Level 3 - "Chain-computations" like on level 2, but 3+ calculations. Still, no equations, i.e. you are not forced to solve it in an algebraic manner. Example exercise
Level 4 - Exercise needs to be solved by algebraic equations, not possible to calculate numerical "in-between" results. Example exercise
Level 5 -
Level 6 -
Question
Solution
Short
Video
\(\LaTeX\)
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Don't forget to subscribe to our channel, like the videos and leave comments!
Exercise:
Ein Körper werde unter einem Winkel von alpO gegenüber der Horizontalen so von einem hohen Gebäude geschossen dass er syhO totale Höhe über dem Boden erreicht und in sxO horizontaler Entfernung vom Fusse des Turmes landet. Aus welcher Höhe wurde der Körper abgeschossen?
Solution:
boxGegeben alpha ang s_y m s_x m boxGesucht textAbschusss-Höhe ssimeter Für die Wurfweite gilt: s_x v_x t v_ cosalpha leftt_uparrow +t_downarrowright v_ cosalpha leftfracv_yg +sqrtfracs_ygright v_ cosalpha leftfracv_sinalphag +sqrtfracs_ygright v_ cosalpha fracv_sinalphag + v_ cosalpha sqrtfracs_yg fracsinalphag v_^ + sqrtfracs_yg cos alpha v_ -s_x . x^ + . x - Die Lösung dieser quadratischen Gleichung ist: v_' -.meterpersecond v_ .meterpersecond Die zweite Lösung ist die physikalisch sinnvolle Lösung. Aus der totalen Wurfhöhe s_y h + fracv_y^g h + fracv_sinalpha^g erhalten wir nun die Abwurfhöhe: h s_y - fracv_sinalpha^g m - fracleft.meterpersecond sin angright^ .meterpersecondsquared .m
Ein Körper werde unter einem Winkel von alpO gegenüber der Horizontalen so von einem hohen Gebäude geschossen dass er syhO totale Höhe über dem Boden erreicht und in sxO horizontaler Entfernung vom Fusse des Turmes landet. Aus welcher Höhe wurde der Körper abgeschossen?
Solution:
boxGegeben alpha ang s_y m s_x m boxGesucht textAbschusss-Höhe ssimeter Für die Wurfweite gilt: s_x v_x t v_ cosalpha leftt_uparrow +t_downarrowright v_ cosalpha leftfracv_yg +sqrtfracs_ygright v_ cosalpha leftfracv_sinalphag +sqrtfracs_ygright v_ cosalpha fracv_sinalphag + v_ cosalpha sqrtfracs_yg fracsinalphag v_^ + sqrtfracs_yg cos alpha v_ -s_x . x^ + . x - Die Lösung dieser quadratischen Gleichung ist: v_' -.meterpersecond v_ .meterpersecond Die zweite Lösung ist die physikalisch sinnvolle Lösung. Aus der totalen Wurfhöhe s_y h + fracv_y^g h + fracv_sinalpha^g erhalten wir nun die Abwurfhöhe: h s_y - fracv_sinalpha^g m - fracleft.meterpersecond sin angright^ .meterpersecondsquared .m
Meta Information
Exercise:
Ein Körper werde unter einem Winkel von alpO gegenüber der Horizontalen so von einem hohen Gebäude geschossen dass er syhO totale Höhe über dem Boden erreicht und in sxO horizontaler Entfernung vom Fusse des Turmes landet. Aus welcher Höhe wurde der Körper abgeschossen?
Solution:
boxGegeben alpha ang s_y m s_x m boxGesucht textAbschusss-Höhe ssimeter Für die Wurfweite gilt: s_x v_x t v_ cosalpha leftt_uparrow +t_downarrowright v_ cosalpha leftfracv_yg +sqrtfracs_ygright v_ cosalpha leftfracv_sinalphag +sqrtfracs_ygright v_ cosalpha fracv_sinalphag + v_ cosalpha sqrtfracs_yg fracsinalphag v_^ + sqrtfracs_yg cos alpha v_ -s_x . x^ + . x - Die Lösung dieser quadratischen Gleichung ist: v_' -.meterpersecond v_ .meterpersecond Die zweite Lösung ist die physikalisch sinnvolle Lösung. Aus der totalen Wurfhöhe s_y h + fracv_y^g h + fracv_sinalpha^g erhalten wir nun die Abwurfhöhe: h s_y - fracv_sinalpha^g m - fracleft.meterpersecond sin angright^ .meterpersecondsquared .m
Ein Körper werde unter einem Winkel von alpO gegenüber der Horizontalen so von einem hohen Gebäude geschossen dass er syhO totale Höhe über dem Boden erreicht und in sxO horizontaler Entfernung vom Fusse des Turmes landet. Aus welcher Höhe wurde der Körper abgeschossen?
Solution:
boxGegeben alpha ang s_y m s_x m boxGesucht textAbschusss-Höhe ssimeter Für die Wurfweite gilt: s_x v_x t v_ cosalpha leftt_uparrow +t_downarrowright v_ cosalpha leftfracv_yg +sqrtfracs_ygright v_ cosalpha leftfracv_sinalphag +sqrtfracs_ygright v_ cosalpha fracv_sinalphag + v_ cosalpha sqrtfracs_yg fracsinalphag v_^ + sqrtfracs_yg cos alpha v_ -s_x . x^ + . x - Die Lösung dieser quadratischen Gleichung ist: v_' -.meterpersecond v_ .meterpersecond Die zweite Lösung ist die physikalisch sinnvolle Lösung. Aus der totalen Wurfhöhe s_y h + fracv_y^g h + fracv_sinalpha^g erhalten wir nun die Abwurfhöhe: h s_y - fracv_sinalpha^g m - fracleft.meterpersecond sin angright^ .meterpersecondsquared .m
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Schiefer Wurf von Turm by TeXercises
Asked Quantity:
Höhe \(h\)
in
Meter \(\rm m\)
Physical Quantity
lotrechter Abstand von Referenzfläche
Unit
Der Meter ist dadurch definiert, dass der Lichtgeschwindigkeit im Vakuum \(c\) ein fester Wert zugewiesen wurde und die Sekunde (\(\rm s\)) ebenfalls über eine Naturkonstante, die Schwingungsfrequenz definiert ist.
Base?
SI?
Metric?
Coherent?
Imperial?